mathsurgent
posted by Anonymous .
Suppose
a+4b+9c+16d+25e=13,
4a+9b+16c +25d +36e =8,
9a+16b+25c+36d+49e=3,
Find the value of
16a+25b+36c+49d+64e=?

mathsurgent 
drwls
Are you sure your third equation is not
9a+ 16b+ 25c +36d +49e = 3 ?
Then it would fall into a certain pattern with the others.
16a +25b +36c +49d +64e = +2
In general, your first three equations in five unknowns have an infinite number of possible solutions, so that the fourth equation cannot be solved uniquely 
mathsurgent 
confused
price of a home is 164,000. bank requires a 20% down payment and 3 points at closing. the cost of the home is financed with a 30 year fixed rate mortgage at 9%

note to "confused" 
drwls
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