chemistryy
posted by p .
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 4.548 x 10^10m. Determine the frequency (in hz) of the interacting photon.
i got 1.45691908531e24 but it is wrong :(

9.14E18

9.14E18 is wrong
can you please explain how you got this number 
E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
E(first ionization)=21.7*10^19
Me= 9.1*10^31
h= 6.626*10^34
frecuency(hz)= E / h 
Yup, it was meant to be wrong.
I don't like cheats. 
when you gave the people wrong answer and you know that it is wrong, this is the pure cheating, stupid..!!

5.043661*10^15
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