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Chemistry

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The solubility of bismuth iodide (BiI3) in water is 10.291 x 10-3 M. Calculate the value of the solubility product. The dissolution products are Bi3+(aq) and I−(aq)

  • Chemistry -

    .........BiI3 ==> Bi^3+ + 3I^-
    Equil..solid.10.291E-3..3*10.291E-3

    Substitute into Ksp expression and solve.

  • Chemistry -

    6.8e-8

  • Chemistry -

    6.8e-8 is oncorrect!

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