# Chemistry

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HELP!!!

At temperatures above 930 ∘C, PbO reduces PbS to form metallic lead (Pb). The byproduct of the reaction is SO2. Calculate the amount of lead produced (in kg) when a reactor is charged with 487.0 kg of PbS and 750 kg of PbO.

• Chemistry -

Looks like the reaction is

2PbO + PbS = 3Pb + SO2

487kg PbS = 487000/239.26 = 2035.44 moles
750kg PbO = 750000/223.20 = 3360.22 moles

Since each PbS needs two PbO, the PbO is the limiting reagent.

Each 2 moles of PbO produce 3 moles of Pb, so we end up with

3/2 * 3360.22mole * 207.2g/mol = 1044.36kg Pb

• Chemistry -

Its wrong

• Chemistry -

pbo in gram/ 446.4 = ans *621.6 = final ans

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