chemistry
posted by schoolgirl .
A photon interacts with a ground state electron in a hydrogen atom and is absorbed. The electron is ejected from the atom and exhibits a de Broglie wavelength of 3.188*10^10m Determine the frequency (in hz) of the interacting photon.

chemistry 
drwls
The momentum of the electron is h /(wavelength)
h is Planck's constant. Use that to compute the electron energy.
Add the electron energy to the ionization energy (13.6 eV) for the photon energy. 
chemistry 
helper
4.7E15

chemistry 
Anonymous
WRONG EXPALIN PLEASE

chemistry 
qwerty
E = P^2/2Me + E(first ionization)
P= h / BroglieWavelength
E(first ionization)=21.7*10^19
Me= 9.1*10^31
h= 6.626*10^34
frecuency(hz)= E / h 
chemistry 
a
i put the numbers into the formula but didn't worked..where's my fault? my E=5.796*10^31 ; my f=874.8039
maybe someone can tell me please what's wrong here, thx
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