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chemistry

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(a) The solubility of bismuth iodide in water is 9.091 x 10-3 M. Calculate the value of the solubility product. The dissolution products are and

  • chemistry -

    solubility = (x)*((x*3))^3

    x=9.091*10-3

    solubility = 1.84*10^-7

  • chemistry -

    u r the best!

  • chemistry -

    5.043*10^-7

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