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chemistry

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) The solubility of bismuth iodide (BiI3) in water is 5.891 x 10-3 M. Calculate the value of the solubility product. The dissolution products are Bi3+(aq) and I−(aq)

  • chemistry -

    its still little bit confuse, could you explain the deatail?

  • chemistry -

    5.043*10^-7

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