chemistry

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A student is asked to prepare 250.0 mL of 3.5 M copper (II) sulfate from solid copper (II) sulfate pentahydrate. Describe how this solution should be made in the chemistry laboratory.

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    I'm not quite sure if you want 3.5M CuSO4 or 3.5M CuSO4.5H2O. I am assuming the former and want to start with CuSO4.5H2O.

    How many mols CuSO4 do you want? That's M x L = 3.5 x 0.250 = about 0.9 but you need to do that more accurately.
    Since there is 1 mol CuSO4 in 1 mol CuSO4.5H2O, you need the same 0.9 mol CuSO4.5H2O.
    g CuSO4.5H2O = mol CuSO4.5H2O x molar mass CuSO4.5H2O

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    dv

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