differential equations
posted by siddh .
dy/dx=4x/y..verify that the straight lines y=2x are solution curves, provided x doesnt equal 0.
Respond to this Question
Similar Questions

Calculus
dy/dx= (y^2 1)/x 1. Give the general equation of the curves that satisfy this equation. 2. Show that the straight lines y=1 and y=1 are also solutions. 3. Do any of the curves you found in 1) intersect y=1? 
Calculuscheck my answers please
dy/dx= (y^2 1)/x 1. Give the general equation of the curves that satisfy this equation. 2. Show that the straight lines y=1 and y=1 are also solutions 3. Do any of the curves you found in 1) intersect y=1? 
Calculus AB
Verify if the given equations are solutions to the differential equation. dy/dt=k(ya) i) y=1ae^(kt) ii) y=a+Ce^(kt) 
AB Calculus
So I'm supposed to verify the solution of the differential equation. The solution is y=e^(x). The differential equation is 3y' + 4y = e^(x). What is the problem asking me to do here? 
calculus
verify that y=c/x^2 is a general solution of the differential equation y'+(2/x) y=06y=0 then find a particular solution of the differential equation that satisfies the side condition y(1)=2 
Math
What will the graph look like for a system of equations that has no solution? 
Math  PreCalc (12th Grade)
Which statement is true for any linear system of two equations in two variables? 
Differential equations in Calculus...plsssss help?
Suppose that represents the temperature of a cup of coffee set out in a room, where T is expressed in degrees Fahrenheit and t in minutes. A physical principle known as Newtonâ€™s Law of Cooling tells us that dT/dt = 1/15T+5 15T + … 
Differential Equations
Verify whether the given equation(y=c1cos(x+c2)) is a solution to this equation[(d^2y/dx^2)^2 + (dy/dx)^2  1 = 0]. 
Math (Calc) (Differential Equation Solution)
Some of the curves corresponding to different values of C in the general solution of the differential equation are shown in the graph. Find the particular solution that passes through the point (0, 2). y(x^2+y) = C 2xy + (x^2+2y)y' …