posted by Anonymous .
A reaction was performed in which 0.47 g of 2-naphthol was reacted with a slight excess of 1-bromobutane to make 0.29 g of 2-butoxynaphthalene. Calculate the theoretical yield and percent yield for this reaction.
2-naphthol + 1-bromobutane --> 2-butoxynaphthalene
Convert 0.47g 2-naphthol to mols. mol = g/molar mass.
Using the coefficients in the balanced equation, convert mols 2-naphthol to mols 2-butoxynaphthalene.
Convert mol 2-butoxynaphthalene to grams. g = mols x molar mass. This is the theoretical yield.
%yield = (actual yield/theor yield)*100 = ?