posted by Alicia .
A spring has a constant of 2.4 x 10^2 n/m. What force does it take to stretchmit .8m? How much PE is stored in the spring? Make a graph of the constant from .1 to 1.0 meters.
F = k*x where k = 240 N/m
Plug in x = 0.8 m and solve for F
At this amount of stretch, the P.E. is
(1/2) k x^2 (or (1/2)F*x.)
It makes no sense to make a graph of a constant. Do you mean P.E. or F vs x ?
Anyway, we don't provide graphs here.