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A spring has a constant of 2.4 x 10^2 n/m. What force does it take to stretchmit .8m? How much PE is stored in the spring? Make a graph of the constant from .1 to 1.0 meters.

  • Physics -

    F = k*x where k = 240 N/m
    Plug in x = 0.8 m and solve for F

    At this amount of stretch, the P.E. is
    (1/2) k x^2 (or (1/2)F*x.)

    It makes no sense to make a graph of a constant. Do you mean P.E. or F vs x ?

    Anyway, we don't provide graphs here.

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