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When dividing a 3 digit number by a 1 digit number for what divisors can you get a remainder 8?

There will be more than one answer.

To have a remainder of 8, the divisor must be greater than 8. The only single digit greater than 8 is 9, so 9 must be the divisor.

Since 8 is 1 less than 9, the dividend needs to be one less than a multiple of 9. Candidates are values of 3 digits, as the problem states.

The lowest 3-digit number satisfying the condition is 107 (which is 9x12 - 1); the highest is 998 (which is 9x111 - 1).

107 / 9 = 11 R8

125 / 9 = 13 R8

998 / 9 = 110 R8

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