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find all the zeros of f(x)=x3-3x2+4x-12

  • Pre-Cal. -

    you know that are all factors of 12. A little regrouping shows you have

    f(x) = x^3-3x^2+4x-12
    = x^2(x-3) + 4(x-3)
    = (x^2+4)(x-3)

    so, f(x) = 0 at x = 3, ±2i

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