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Two jets are traveling toward each other and are 4000km apart. The rate of one jet is 100km/h faster than the rate of the other. If the jets pass each other after 2.5 hours, what is the rate of the faster jet?

  • math -

    rate of slower jet ---- x km/h
    rate of faster jet ----- x+100 km/h

    solve for x

    2.5x+ 2.5(x+100) = 4000

    (I got x = 750 , so the faster jet goes 850 km/h)

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