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find the equation of a straight line on which the perpendicular from the origin makes an angle of 30 degree with the x-axis and which forms a triangle of are 50/root3 with the axes

  • maths -

    if the base has length x,
    area = 1/2 * x * x√3 = √3/2 x^2 = 50/√3
    x = 10
    so, y = 10√3

    so, the line is

    x/10 + y/(10√3) = 1

  • maths -

    oops. x = 10/√3
    y = 10

    x/(10√3) + y/10 = 1

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