math
posted by Heather .
answer the following for the given quadratic function.
f(x)=x^2+x^28
a. what is the vertex (h,k) of f?
(h,k)=? simplify your answer and type the answer in an ordered pair
b. what is the axis of symmetry?

a. (0,8) is the vertex

b. axis of symmetry is zero.

I have a feeling there is a typo.
Why would anybody have two like terms in the equation ?
should it be
f(x) = x^2 + 2x  8 ???? 
Yes, Reiny you caught the typo
It should read f(x)=x^2+2x8, thank you for catching that. So, now my answers will change that Riana gave. Right? 
yes,
complete the square ....
f(x) = x^2 + 2x +1  1 8
= (x+1)^2  9
vertex is (1,9)
axis of symmetry: x = 1 or x+1 = 0 
then your vertex is (2,8)
and axis will be 1 
the vertex can't be (1,9) its incorrect.

NO, check my reply

Yes it is !
http://www.wolframalpha.com/input/?i=plot+x%5E2+%2B+2x++8
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