solve the exponential equation. Express the solution in terms of natural logarithms.

e^x=9.2

a. whats the solution in terms of natural logarithms?
**is the answer e^9.2 or just e^9

b. type a decimal rounded to 3 decimal places.

Why would you think to drop the decimal of the 9.2 ??

btw, the answer is ln(9.2) not e^9.2 , just look at the instructions you have in your post

To solve the exponential equation e^x = 9.2 and express the solution in terms of natural logarithms, we can use the property of logarithms that states: if a^x = y, then log base a of y equals x.

Step 1: Take the natural logarithm (ln) of both sides of the equation to get rid of the exponential.
ln(e^x) = ln(9.2)

The natural logarithm of e is 1, so the left side simplifies to just x:
x = ln(9.2)

Therefore, the solution in terms of natural logarithms is x = ln(9.2).

Now, to find a decimal approximation rounded to 3 decimal places, you can use a calculator or a math software. In this case, the approximate value of ln(9.2) is approximately 2.219 according to most calculators.

Therefore, a decimal rounded to 3 decimal places is x ≈ 2.219.