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An arrow is shot at an angle 35 ◦ with the horizontal. It has a velocity of 47 m/s. How high will the arrow go? The acceleration of gravity is 9.8 m/s 2 .
Answer in units of m

  • physics -

    Vo = 47m/s @ 35o.
    Yo = 47*sin35 = 27 m/s = Ver. component
    of initial velocity.

    Y^2 = Yo^2 + 2g*h.
    h = (Y^2-Yo^2)/2g.
    h = (0-729)/-19.6 = 37.2 m.

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