calculus

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Solve the equation in the real number system

X^4+11x^3+24x^2-23x+35=0

Please show work

  • calculus -

    the 35 tempts me to try -7 and -
    divide mess by (x+5)
    get
    (x+5)(x^3+6x^2-6x+7)
    so divide
    (x^3+6x^2-6x+7) by (x+7)
    get
    (x+5)(x+7)(x^2-x+1)
    now that last one has no real roots
    b^2-4ac = 1-4 = -3
    so our only real roots are
    (-5,0) and (-7,0)

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