calculus
posted by Austin .
Solve the equation in the real number system
X^4+11x^3+24x^223x+35=0
Please show work

the 35 tempts me to try 7 and 
divide mess by (x+5)
get
(x+5)(x^3+6x^26x+7)
so divide
(x^3+6x^26x+7) by (x+7)
get
(x+5)(x+7)(x^2x+1)
now that last one has no real roots
b^24ac = 14 = 3
so our only real roots are
(5,0) and (7,0)
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