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calculus-can someone please help me with this ques

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Find all zeros of the following polynomial. Write the polynomial in factored form. f(x)=x^3-3x^2+16x-48

I put: x^2(x-3)+16(x=3)
(x-3)(x^2+16)
For zeros:
x-3=0
x=0
**My teacher stated check the equation solution again. What is the value for x and hence what is the zero for the polynomial based on the first factor?

**Can someone help me?

  • calculus-can someone please help me with this ques -

    You factored the cubic polynomial correctly as
    (x-3)(x^2 + 16)
    The first term tells the function has a zero at x = 3.
    The other roots are imaginary. x = +/- 4i

  • calculus-can someone please help me with this ques -

    yes, I did put:
    x^2+16=0
    x^2= -16
    x= + or -4i

    But she wrote that on the first part that I submitted and I don't really know what it is that she wants me to do.
    **So are you saying that the value for x is 3, but then what is the zero for the polynomial based on the first factor??

  • calculus-can someone please help me with this ques -

    x-3 = 0
    means x = 0
    so the polynomial is zero at x = 3
    also at - 4 i and at + 4 i

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