Post a New Question

Physics

posted by .

An attack helicopter is equipped with a 20-
mm cannon that fires 198 g shells in the
forward direction with a muzzle speed of
711 m/s. The fully loaded helicopter has a
mass of 4810 kg. A burst of 75.3 shells is fired
in a 6.27 s interval.
What is the resulting average force on the
helicopter?
Answer in units of N

  • Physics -

    The fired shells exert a backward force on the helicopter that equals the rate that forward momentum is created for the shells.

    F = (75.3)(0.198)*(711)/6.27 = 1691 N

    kg*m/s*(1/s) = Newtons

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question