# calculus

posted by .

find all zeros of the following polynomial. write the polynomial in factored form.

f(x)=x^3-3x^2+16x-48

• calculus -

Try + and - the prime factors of 48:
1, 2, 3, 4, 6, 8, 12 and 16.
When you find one that works, call it 'a' and divide the f(x) polymonial by (x-a) to get the quadratic factor. The other two roots can easily be found with that.

It looks to me like one root is +3. Therefore x-3 is a factor.

Now evaluate [x^3-3x^2+16x-48]/(x-3)

It should give you a quadratic equation with no remainder. Factor that.

## Similar Questions

1. ### College Algebra

Find all zeros of the following polynomial. Write th polynomial in factored form. f(x) = x^4 - 256
2. ### college algebra

find the complex zeros of the polynomial function. write f in factored form. use complex zeros to write f in factored form f(x)= x^3-6x^2+21x-26
3. ### pre-calculus

find the complex zeros of the polynomial function. write F in the factored form. f(X)=x^3-7x^2+20x-24 use the complex zeros to write f in factored form. f(x)= (reduce fractions and simplify roots)
4. ### calculus

find the complex zeros of the polynomial function. write f in factored form. f(x)=x^3-10x^2+42x-72 please show work.
5. ### calculus

can someone please help me find all the zeros of the following polynomial. write the polynomial in factored form. f(x)=x^3-3x^2+16x-48 can you please show all work
6. ### Pre-Cal.

find all the zeros of the following polynomial. Write the polynomial in fraction form. Show all the work. f(x)= x^4+3x^2-40