calculus
posted by ladybug .
find all zeros of the following polynomial. write the polynomial in factored form.
f(x)=x^33x^2+16x48

Try + and  the prime factors of 48:
1, 2, 3, 4, 6, 8, 12 and 16.
When you find one that works, call it 'a' and divide the f(x) polymonial by (xa) to get the quadratic factor. The other two roots can easily be found with that.
It looks to me like one root is +3. Therefore x3 is a factor.
Now evaluate [x^33x^2+16x48]/(x3)
It should give you a quadratic equation with no remainder. Factor that.