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Find three consecutive odd integers such that the square of the first increased by product of the other two is 224.

  • Math -

    let the middle number be x
    then the 1st is x-2
    and the 3rd is x+2

    (x-2)^2 + x(x+2) = 224
    x^2 - 4x + 4 + x^2 + 2x = 224
    2x^2 -2x - 220 = 0
    x^2 - x - 110 = 0
    (x-11)(x+10) = 0
    x = 11 or x = -10, but x is to be odd
    so
    x = 11
    and the three numbers are 9, 11, and 13

    check:
    9^2 + 11(13) = 224 , YEAH!

  • Math -

    i got this so correct omg im so happy

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