a bag contains 5 blue marbles 4 red marbles and 1 green marble. what is the probability of drawing a blue marble,the another blue marble without replacement

Prob(blue,blue) = (5/10)(4/9) = 20/90 = 2/9

thank you so much!!

To find the probability of drawing a blue marble and then another blue marble without replacement, we need to consider the total number of marbles and the number of possible outcomes.

Step 1: Calculate the probability of drawing the first blue marble.
The bag contains a total of 5 + 4 + 1 = 10 marbles. Since there are 5 blue marbles, the probability of drawing a blue marble on the first draw is 5/10.

Step 2: Calculate the probability of drawing the second blue marble without replacement.
After drawing the first blue marble, there are 4 blue marbles remaining, out of a total of 9 marbles left in the bag. Therefore, the probability of drawing another blue marble without replacement is 4/9.

Step 3: Multiply the probabilities.
To find the probability of two events occurring together, we multiply their individual probabilities. So, the probability of drawing a blue marble and then another blue marble without replacement is (5/10) * (4/9) = 2/9 or approximately 0.2222.

Therefore, the probability of drawing a blue marble and then another blue marble without replacement is 2/9.