posted by Jimmy-can someone please help .
Determine the quadratic function f, whose graph is given. **The graph given is (0,-2) and (3,-11)
The vertex is (3,11) and the y-intercept is -2
**Please help me understand how to do this question. Could you please show work?**
come on, guy. You should be getting the hang of these by now.
the vertex says
f(x) = a(x-3)^2 + 11
the point (0,-2) says
-2 = 9a+11
a = -13/9
f(x) = -13/9 (x-3)^2 + 11
would have been nicer with a y-intercept of +2.