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find the volume of the solid generated by revolving the region about the given line. the region in the first quadrant bound above by the line y=1, below by the curve y=√(sin5x) ,and on the left by the y-axis, above the line y=-1

  • calculus -

    What is the "given line" that the solid volume revolves around?

  • calculus -

    Should the word "above" in the last line be "about"? Then the question would make sense.

  • calculas -

    using washers, the volume is

    ∫[0,π/10] π R^2-r^2 dx
    where R=2 and r = √(sin5x) + 1

    v = ∫[0,π/10] π (4 - (√(sin5x)+1)^2) dx


    I think you are in trouble.

    ∫√(sin5x) dx

    cannot be evaluated using elementary functions.

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