Math For College Readiness
posted by Neil .
Simplify:
y  3 / y  2  y + 1 / 2y  5 + 4y + 7 / 2y^2  9y + 10

I'm sure there are some missing parentheses. Making a guess, I'd say you meant
(y3)/(y2)  (y+1)/(2y5) + (4y+7)/(2y^29y+10)
putting all over a common denominator, we have
[(y3)(2y5)  (y+1)(y2) + (4y+7)]/(2y^29y+10)
((2y^211y+15)  (y^2y2) + (4y+7))/(2y^29y+10)
= (y^214y+24)/(2y^29y+10)
= (y2)(y12)/[(y2)(2y5)]
= (y12)/(2y5) 
Thank you very much. Yeah, I should've added the parenthesis to make it look familiar.