Calculus
posted by Corey .
Find the area between the following curves y1= x2−4x+3 y2=−x2+2x+3

The curves intersect at (0,4) and (3,0)
area = ∫[0,3] (x^2+2x+3)  (x^24x+3) dx
= ∫[03] 6x  2x^2 dx
= 3x^2  2/3 x^3 [0,3]
= 9
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