Statistics

posted by .

A computer repair service found that a random sample of 45 repair costs had a mean cost of $659. Assume that the population standard deviation is $125. Calculate the margin of error, E, for a 95% confidence interval for the population mean µ.

  • Statistics -

    95% = mean ± 1.96 SEm

    SEm = SD/√n

    I'll let you do the calculations.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. statistics

    what are the mean and standard deviation of a sampling distribution consisting of samples of size 16?
  2. Statistics

    The following data set represents the repair costs (in dollars) for a random sample of 30 dishwashers. 41.82 52.81 57.80 68.16 73.48 78.88 88.13 88.79 90.07 90.35 91.68 91.72 93.01 95.21 95.34 96.50 100.05 101.32 103.59 104.19 105.62 …
  3. statistics

    A simple random sample of 60 items resulted in a sample mean of 80. The population standard deviation is 15. a) Compute the 95 % confidence interval for the population mean. b) Assume that the same sample mean was obtained from a sample …
  4. Statistics

    Computer Depot is a large store that sells and repairs computers. A random sample of 110 computer repair jobs took technicians an average of 93.2 minutes per computer. Assume that o is known to be 16.9 minutes. Find a 99% confidence …
  5. Statistics

    A 95% confidence interval for a population mean, ?
  6. Statistics

    What is the appropriate sample size for a confidence interval around the sample mean if you want a margin of error of 0.8 with 95% confidence and a population standard deviation of 12.
  7. statistics

    The average cost per night of a hotel room in New York City is $273 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $65. a. With 95% confidence, what is the …
  8. statistics (7)

    The average cost per night of a hotel room in New York City is $273 (SmartMoney, March 2009). Assume this estimate is based on a sample of 45 hotels and that the sample standard deviation is $65. a. With 95% confidence, what is the …
  9. Statistics (42)

    A simple random sample of 60 items resulted in a sample mean of 96. The population standard deviation is 16. a. Compute the 95% confidence interval for the population mean (to 1 decimal). ( , ) b. Assume that the same sample mean was …
  10. Economics (41)

    A simple random sample of 60 items resulted in a sample mean of 96. The population standard deviation is 16. a. Compute the 95% confidence interval for the population mean (to 1 decimal). ( , ) b. Assume that the same sample mean was …

More Similar Questions