A Ferris wheel has a radius of 25 feet.The wheel is rotating at two revolutions per minute.Find the linear speed, in feet per minute, of a seat on this ferris wheel.
2 rpm is an angular speed of
w = 4 pi radians/min
The linear speed is R*w
Do the numbers. Looks like 100 pi ft/min
ty
A ferris wheel has a diameter of approximately 55 meters. The wheel rotates once every
44 minutes. Find the linear speed at the outer edge of the ferris wheel in meters per hour.
To find the linear speed of a seat on the Ferris wheel, we need to determine the circumference of the wheel and then multiply it by the number of revolutions per minute.
The circumference of a circle can be calculated using the formula: C = 2πr, where C is the circumference, π is a mathematical constant approximately equal to 3.14159, and r is the radius.
In this case, the radius of the Ferris wheel is given as 25 feet. Therefore, the circumference is:
C = 2π * 25
C ≈ 2 * 3.14159 * 25
C ≈ 6.28318 * 25
C ≈ 157.07963 feet
Thus, the circumference of the Ferris wheel is approximately 157.07963 feet.
Since the wheel is rotating at two revolutions per minute, the linear speed of a seat on the Ferris wheel is given by:
Linear Speed = Circumference * Number of Revolutions per Minute
Linear Speed ≈ 157.07963 * 2
Linear Speed ≈ 314.15926 feet per minute
Therefore, the linear speed of a seat on this Ferris wheel is approximately 314.15926 feet per minute.