150.0ml of iron(iii)chloride solution is mixed with 180.0ml of the sodium hydroxide solution,1.65g yield of experimental iron(iii)hydroxide is obtained.find the theoretical yeild of the precipitate.
how you find that ?
See your other posts below.
plz just tell me the method. :)
It's below. No point in me writing it all over again.
Where below??
To find the theoretical yield of the precipitate (iron(III) hydroxide), we need to determine the limiting reactant in the reaction between iron(III) chloride and sodium hydroxide. The limiting reactant is the one that is completely consumed and determines the maximum amount of product that can be formed.
To find the limiting reactant, we compare the number of moles of each reactant with their respective stoichiometric coefficients in the balanced chemical equation.
First, we need to establish the balanced chemical equation for the reaction between iron(III) chloride and sodium hydroxide:
FeCl3 + 3NaOH → Fe(OH)3 + 3NaCl
From the equation, we can see that 1 mole of FeCl3 will react with 3 moles of NaOH to produce 1 mole of Fe(OH)3.
Next, let's calculate the number of moles of each reactant:
Molar mass of FeCl3 = 162.2 g/mol
Number of moles of FeCl3 = (150.0 ml / 1000 ml) * 1.65 g / 162.2 g/mol
Molar mass of NaOH = 40.0 g/mol
Number of moles of NaOH = (180.0 ml / 1000 ml) * 40.0 g / 40.0 g/mol
Now, let's determine which reactant is the limiting reactant:
Since the stoichiometric ratio between FeCl3 and NaOH is 1:3, we can calculate the equivalent number of moles of NaOH needed to react with the amount of FeCl3 we have:
Equivalent moles of NaOH = (Number of moles of FeCl3) * (3 moles of NaOH / 1 mole of FeCl3)
Compare the calculated equivalent moles of NaOH with the actual number of moles of NaOH:
If the actual number of moles of NaOH is greater than the equivalent moles of NaOH, then NaOH is in excess and FeCl3 is the limiting reactant.
If the actual number of moles of NaOH is smaller than the equivalent moles of NaOH, then NaOH is the limiting reactant.
Once we determine the limiting reactant, we can use its stoichiometric ratio with the desired product (Fe(OH)3) to calculate the theoretical yield:
Theoretical yield of Fe(OH)3 = (Number of moles of limiting reactant) * (Molar mass of Fe(OH)3) / (Stoichiometry between limiting reactant and Fe(OH)3)
Finally, multiply the theoretical yield (in moles) by the molar mass of Fe(OH)3 to obtain the answer in grams.