x2+7x+10
2X+7X+10=0
9X+10=0
9X=-10
X=-10/9 FINAL ANSWER
(Variable and constant can not write on one side of the equaiton.
I'm pretty sure the equation to solve is
x^2 + 7x + 10 = 0
(x+5)(x+2) = 0
x = -2 or -5
To solve the quadratic expression x^2 + 7x + 10, you can use the quadratic formula or factorization method. I will explain both methods:
Method 1: Quadratic Formula
The quadratic formula is used to solve any quadratic equation. A quadratic equation is in the form ax^2 + bx + c = 0, where a, b, and c are coefficients.
In this case, a = 1, b = 7, and c = 10. Substituting these values into the quadratic formula, we have:
x = (-b ± √(b^2 - 4ac)) / (2a)
Plugging in the values, we get:
x = (-(7) ± √((7)^2 - 4(1)(10))) / (2(1))
x = (-7 ± √(49 - 40)) / 2
x = (-7 ± √9) / 2
x = (-7 ± 3) / 2
This gives us two solutions: x = (-7 + 3) / 2 and x = (-7 - 3) / 2.
Simplifying further, we get:
x = (-4) / 2 = -2
x = (-10) / 2 = -5
Therefore, the solutions to the quadratic equation x^2 + 7x + 10 = 0 are x = -2 and x = -5.
Method 2: Factorization
Factorization involves breaking down the quadratic expression into two binomial factors. Here's how to factorize x^2 + 7x + 10:
Step 1: Find two numbers whose sum is equal to the coefficient of the middle term (7) and whose product is equal to the product of the first and last terms (1 * 10 = 10).
The numbers are 2 and 5 because 2 + 5 = 7 and 2 * 5 = 10.
Step 2: Rewrite the quadratic expression using the numbers found:
x^2 + 2x + 5x + 10
Step 3: Group the terms and factor them:
(x^2 + 2x) + (5x + 10)
x(x + 2) + 5(x + 2)
Step 4: Combine the common factors:
(x + 2)(x + 5)
Hence, the quadratic expression x^2 + 7x + 10 can be factored as (x + 2)(x + 5).
Using either method, we find that the solutions to x^2 + 7x + 10 = 0 are x = -2 and x = -5.