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Chemistry

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Balance the following equation. (for a balanced eq. aA + bB → cC + dD, enter your answer as the integer abcd)

MnO4−(aq) + SO32−(aq) + H+(aq) → Mn2+(aq) + SO42−(aq) + H2O(l)
i got 2525 and its going in as incorrect

Now you get to balance this equation (answer in the same way as in the problem above):

Al(s) + NO3−(aq) + OH−(aq) + H2O → Al(OH)4−(aq) + NH3(g)

i go 2121 but its not correct

  • Chemistry -

    MnO4−(aq) + SO32−(aq) + H+(aq) → Mn2+(aq) + SO42−(aq) + H2O(l)

    in the form

    a*MnO4−(aq) + b*SO32−(aq) + c*H+(aq) → d*Mn2+(aq) + e*SO42−(aq) + f*H2O(l)

    Start by counting how many of each are on each side. I'm going to choose to use the convention [element (left, right)]
    Mn(1,1)
    O(7,5)
    S(1,1)
    H(1,2)

    b=e; (Balancing the sulfur, S)
    a=d; (Balancing the Mn)
    c=2*f; (Balancing the hydrogen)
    3*b + 4*a = 4*e + f (Balancing the oxygen)

    So let a=e = 1; b=1; f=3
    (3*1 + 4*1 = 4*1 + 3)
    d=1
    c=6

    So the equation is
    MnO4−(aq) + SO32−(aq) + 6H+(aq) → Mn2+(aq) + SO42−(aq) + 3H2O(l)

    2nd problem:
    Al(s) + NO3−(aq) + OH−(aq) + H2O → Al(OH)4−(aq) + NH3(g)

    of the form

    a*Al(s) + b*NO3−(aq) + c*OH−(aq) + d*H2O → e*Al(OH)4−(aq) + f*NH3(g)

    Al(1,1)
    N(1,1)
    O(5,4)
    H(3,7)

    a=e (balancing the aluminum)
    b=f (balancing the nitrogen)
    3*b + c + d = 4*e (balancing the oxygen)
    c + 2*d = 4*e + 3*f (Balancing the hydrogen)

    You should be able to experiment with numbers and balance this out

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