How many grams of acetic acid must be dissolved to produce 3875 ml with a Ph of 2.9?

pH = 2.9 = -log(H^+)

Solve for (H^+) = 0.00126M
........HAc ==> H^+ + Ac^-
E.......x..0.00126..0.00126
Ka = (H^+)(Ac^-)/(HAc)
Substitute and solve for (HAc).
grams = mols x molar mass
g/L x 3.875 L = g/3875 mL.

To determine the number of grams of acetic acid needed to produce a solution with a pH of 2.9, we need to take into consideration the dissociation of acetic acid (CH3COOH) in water. Acetic acid is a weak acid, meaning it only partially dissociates in water.

The pH of a solution indicates its acidity or basicity. In this case, a pH of 2.9 indicates the solution is quite acidic. The pH scale ranges from 0 to 14, with values below 7 being acidic and values above 7 being basic.

To calculate the number of grams of acetic acid needed, we need to follow these steps:

1. Calculate the concentration of hydrogen ions in the final solution using the pH:
pH = -log[H+]
Rearrange the equation to solve for [H+]:
[H+] = 10^(-pH)

Substituting the pH value of 2.9 into the equation:
[H+] = 10^(-2.9)
[H+] = 1.2589 x 10^(-3) (approximately)

2. Since acetic acid is a weak acid, it will not completely dissociate in water. Instead, it dissociates into hydrogen ions (H+) and acetate ions (CH3COO-). The mole ratio of acetic acid to hydrogen ions is 1:1, meaning one mole of acetic acid produces one mole of hydrogen ions.

3. The molar concentration (M) of acetic acid can be determined by the following equation:
M = moles of solute / volume of solution (in liters)

Since we are given the volume of the solution in milliliters (3875 mL), we need to convert it into liters by dividing it by 1000:
Volume of solution = 3875 mL / 1000 = 3.875 L

4. To find the moles of acetic acid needed, we multiply the concentration of hydrogen ions by the volume of the solution:
Moles of acetic acid = [H+] x volume of solution

Substituting the values we obtained earlier:
Moles of acetic acid = 1.2589 x 10^(-3) x 3.875

5. Finally, to find the grams of acetic acid needed, we multiply the number of moles by the molar mass of acetic acid (60.05 g/mol):
Grams of acetic acid = Moles of acetic acid x molar mass of acetic acid

Substituting the values into the equation:
Grams of acetic acid = (1.2589 x 10^(-3) x 3.875) x 60.05

Calculating this expression will give you the final answer in grams.