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ind two consecutive even integers such that the smaller added to five times the larger is 58

  • math -

    Let the smaller even integer be n.
    The larger is then n+2.
    The problem says
    "smaller added to five times the larger is 58"
    which translates to
    n+5(n+2)=58
    Solve for n (smaller even integer)

  • math -

    a = first number

    b = second number


    b = a + 2


    a + 5 ( a + 2 ) = 58

    a + 5 a + 10 = 58

    6 a + 10 = 58 Subtrac 10 to both sides

    6 a + 10 - 10 = 58 - 10

    6 a = 48 Divide both sides by 6

    6 a / 6 = 48 / 6

    a = 8

    b = a + 2 = 8 + 2 = 10


    Your numbers are 8 and 10

    8 + 5 * 10 = 8 + 50 = 58

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