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A plank with m=0.12 kg and 50cm long has one mass of m1=0.11kg sitting on one end and a m2=0.055kg at the other end. Where should the pivot point be to balance the plank?

  • physics -

    I figured the equation out
    Xcg=(m1x1+m2x2+m3(L/2))/(m1+m2+m3)

    m1 = 0.055kg
    x1 = 0cm

    m2 = 0.11kg
    x2 = 50cm

    for the plank you need to add
    m3 = 0.12kg
    and distance is L=50cm

    it calculates to Xcg=29.825cm

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