# calculus

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find all discontinuities (16x/2x3-8x3=0)

• calculus -

You are probably not getting a reply because this is a confusing question.

you write it as an equation, equations have solutions, we don't speak of discontinuities for equations

Secondly, is the denominator 2x^3 - 8x^3
or only 2x^3 , the way you typed it.

Thirdly, if the denominator is 2x^3 - 8x^3, why was it not simplified to -6x^3

Is there a typo??

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