calculus
posted by brianna .
find all discontinuities (16x/2x38x3=0)

You are probably not getting a reply because this is a confusing question.
you write it as an equation, equations have solutions, we don't speak of discontinuities for equations
Secondly, is the denominator 2x^3  8x^3
or only 2x^3 , the way you typed it.
Thirdly, if the denominator is 2x^3  8x^3, why was it not simplified to 6x^3
Is there a typo??
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