CS2 + O2 -> CO2 + SO2 and 10.0 grams of each reactant, calculate the number of moles of SO2 that can be produced in this reaction
since you have 10g of each available, the compound with the heaviest mol wt will be the limiting reagent.
so, which is heavier, CS2 or O2?
Once you balance your equation, you can figure the amount of SO2.
To calculate the number of moles of SO2 that can be produced in the reaction, you need to compare the ratios of the reactants and products given by the balanced chemical equation.
The balanced chemical equation is: CS2 + O2 -> CO2 + SO2
From the balanced equation, you can see that the molar ratio between CS2 and SO2 is 1:1. This means that for every 1 mole of CS2 reacted, 1 mole of SO2 is produced.
Now, you have 10.0 grams of CS2. To convert this mass to moles, you need to know the molar mass of CS2. Carbon has a molar mass of 12 g/mol, and sulfur has a molar mass of 32.06 g/mol. Since there are two atoms of sulfur in CS2, the molar mass of CS2 is 12 + (2 x 32.06) = 76.12 g/mol.
Using the molar mass of CS2, you can calculate the number of moles:
Number of moles = Mass / Molar mass
Number of moles of CS2 = 10.0 g / 76.12 g/mol
Similarly, according to the balanced equation, the molar ratio between O2 and SO2 is 1:1. This means that for every 1 mole of O2 reacted, 1 mole of SO2 is produced.
Now, you have 10.0 grams of O2. To convert this mass to moles, you need to know the molar mass of O2, which is 32 g/mol.
Number of moles of O2 = 10.0 g / 32 g/mol
Since the ratio of CS2 to SO2 is 1:1 and the ratio of O2 to SO2 is also 1:1, the smallest number of moles calculated above is the limiting reactant. This means that the number of moles of SO2 that can be produced will be the same as the number of moles of the limiting reactant.
Therefore, the number of moles of SO2 that can be produced in this reaction is equal to the number of moles of either CS2 or O2, whichever is smaller.