physics math

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the acceleration of a car is 2m/s^2 and another car has constant velocity of 35m/s.what time the first car overtake the car with constant velocity of the first car?

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  • physics math -

    first car:
    a = 2 m/s^2
    v = 2t + c
    when t = 0 , v = 0 m/s
    0 = 0 + c , so c=0
    so v = 2t
    d = t^2 + k
    when t = 0, d = 0
    0 = 0 + k, so k=0

    for 1st car: d = t^2

    2nd car:
    v = 35
    d = 35t + c
    when t= 0 , d = 0 , so c = 0

    for 2nd car : d = 35t

    so we want t^2 = 35t
    t^2 - 35t = 0
    t(t-35) = 0
    t = 0 , (at the start they both had traveled no distance)
    or
    t = 35

    the 1st car will catch the second car in 35 seconds

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