Chemistry

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How many moles of glucose , C6H12O6, can be "burned" biologically when 10.0 mol of oxygen is available.
C6H12O6(s) + 602(g)---6CO2(g) + 6H2O(l)

  • Chemistry -

    1.67 mol

  • Chemistry -

    Solving for glucose. 10.0 mol divided by 6 O2 is the answer (1.67)

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