posted by DEEPAK
AT WHAT HEIGHT ABOVE THE EARTH'S SURFACE DOES THE ACCELERATION DUE TO GRAVITY FALL TO 1% OF ITS VALUE AT THE EARTH SURFACE
Solve this equation for height h, in kilometers:
[6378/(6378+h)]^2 = 0.01
Note that an inverse square law is being used.
6378 is the Earth's radius in km.