# SCIENCE

posted by DEEPAK

AT WHAT HEIGHT ABOVE THE EARTH'S SURFACE DOES THE ACCELERATION DUE TO GRAVITY FALL TO 1% OF ITS VALUE AT THE EARTH SURFACE

1. drwls

Solve this equation for height h, in kilometers:

[6378/(6378+h)]^2 = 0.01

Note that an inverse square law is being used.

6378 is the Earth's radius in km.

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