algebra 2
posted by lisa
check my answer please find the number of zeros(xintercepts) y=3k^36k^245k=k(3k+9)(k5)= k(3k^215k+9k45)=k(3k^26k45) or should i do it 3k(k5) (k+3)=3k(k^2+3k5k15)=3k(k^22k15) which on is the right one please let me know.thanks

Mac
Yes you factor
3k(k5)(k+3) and your check says you did it correctly
Now to find the zeros
Set each factor = 0. And solve
3k=0. K=0
K5=0. K=5
K+3=0. K=3
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