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How much 10.0 M HNO3 must be added to 1.00 L of a buffer that is 0.0100 M acetic acid and 0.100 M sodium acetate to reduce the pH to 5.00? pKa of acetic acid= 4.75

  • chemistry -

    1000 mL x 0.01M = 10 millimols HAc
    1000 mL x 0.1M = 100 mmols NaAc

    ..........Ac^- + H^+ ==> HAc
    I........100.....0........10
    add HNO3.........x...........
    C........-x.....-x.........+x
    C.......100-x....0........10+x

    pH = pKa + log [(100-x)/(10+x)]
    Solve for x = mmols HNO3 needed.
    M = mmols/mL. You know mmols and M, solve for mL HNO3. I think the answer is about 3 mL.

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