Post a New Question


posted by .

a woman throws a ball vertically upwards so that 4seconds elapse before it strikes the ground. Determine the maximum height of the ball and the velocity with which the ball was thrown. Assume that the acceleration due to gravity is 10m/s squared and neglect the effect of air resistance

  • calculus -

    the height h(t) is

    h(t) = vt-4.9t^2
    h=0 when t=4, so

    4v-4.9*16 = 0
    v = 19.6

    h(t) = 19.6t - 4.9t^2
    max h at t=2 because of symmetry
    h(2) = 19.6*2 - 4.9*4 = 19.6

Answer This Question

First Name
School Subject
Your Answer

Related Questions

More Related Questions

Post a New Question