So is this right for prime factorization

be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ?

Looks right to me

Thank you !

not to me. 2 appears twice, so you'd have 2^2 * 2^3 = 2^5

What does it multiply too? equal too?

confused now.

How do I write this then ??

"So is this right for prime factorization
be 2 to the 2nd exponent x 3 x 5 to the 4th exponent x 2 the 3rd exponenetx 11 to the 2nd ? "

Statement of notice and recognition of being.

2 to the exponent of 3 3 times 5 to the exponent of 2 and times 11

What is the answer