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Two pipes of equal length are each open at one end. Each has a fundamental frequency of 715 Hz at 300 K. In one pipe the air temperature is increased to 313 K. If the two pipes are sounded together, what beat frequency results?

  • Physics- PLEASE HELP -

    v =331sqrt(T/273)
    v1=331sqrt(300/273) =347 m/s
    v2=331sqrt(313/273) =354 m/s
    Fundamental frequency λ=4L
    f=v/ λ =>
    f1/f2 =v2/v1 =>
    f2=f1(v2/v1)=715(354/347)=729 Hz
    f(beat) =f2-f1= 729-715 =14 Hz

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