math

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Suppose that you must order concrete for a sidewalk that is to be 58 ft by 3 ft to a depth of 6 in. How much concrete is required? (Answer to the nearest 1/2 cubic yard.)


my answe is 11.5 and is wrong.ugh

  • math -

    1 ft = 12 in

    6 in = 0.5 ft

    V = 58 * 3 * 0.5 = 87 ft ^ 3

    1 yd = 3 ft

    1 yd ^ 3 = 3 ^ 2 = 27 ft ^ 3

    87 / 27 = 3.222 yd ^ 3

    approx. 3 yd ^ 3

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