# math

posted by
**greg**
.

Solve sin2x + sin4x = cos2x + cos 4x for x in the interval[0,2pi)

Hint: the following substitution should come in handy: sin3x= cos3x . tan3x

posted by
**greg**
.

Solve sin2x + sin4x = cos2x + cos 4x for x in the interval[0,2pi)

Hint: the following substitution should come in handy: sin3x= cos3x . tan3x