posted by .

How many hours are required for the deposition of 15.0 grams of Al from molten AlCl3 by a current of 15.0 amps?

  • Chemistry -

    It will require 96,485 coulombs to deposit 27/3 = 9 g Al. Therefore, it will require 96,485 x (15/9) coulombs to deposit 15 g.
    1 C = Amp x sec. You know C and amps solve for seconds.

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. Chemistry

    I did a lab where I put Copper (II) Chloride in water with Alumnim. 2Al + 3CuCl2 -> 3Cu + 2AlCl3 The aluminum on the reactant side weighs 0.5 g and the CuClw weighs 1.69 grams. It said to find the theoricital yield. Did I do this …
  2. chemistry

    consider the electrolysis of molten AlCl3 what must the current be in amps if you need to obtain 25.0 grams of aluminum in 5.00 min
  3. Chemistry

    A current of 0.80 A was applied to an electrolytic cell containing molten CdCl2 for 2.5 hours. Calculate the mass (in grams) of cadmium metal deposited. [Enter only numbers in the blank.]
  4. chemistry

    What mass of aluminum metal can be produced per hour in the electrolysis of a molten aluminum salt by a current of 24 amps?
  5. science

    Which one would be the safest? a. a current of 0.001 amps at 120 volts b. a current of 0.0001 amps at 24,000 volts c.a 5 volt source with unlimited current potential
  6. College Chemistry

    How many grams of Al would be deposited from an aqueous solution of Al3+ with a current of 1.430A after 5hrs of deposition.
  7. Science

    If the voltage is110 volts and the total resistance is 10, what is the measure of the current in the circuit?
  8. Science 3

    What is the current in the circuit if R1=7 R 2 =15, and the voltage is 220 volts?
  9. Chemistry

    The thermite reaction was used to weld rail ties together. If 15.0 grams of aluminum were used, how many grams of ferric oxide would be required?
  10. chemistry

    Molten Al2O3 is reduced by electrolysis at low potentials and high currents. If 1.5 x 10^4 amperes of current is passed through molten Al2O3 for 8.0 hours, what mass of Al is produced?

More Similar Questions