How many grams of KHP (204.22 g/mol) were present in container if 49.36 mL of 0.2264M NaOH were needed to reach the end point of a titration? I'm confused on the formula you would use for this.
Most problems in chemistry hinge on mols. A mole reacts with one/two/three/etc mols of some other material.
KHP + NaOH ==> NaKP + H2O
mols NaOH = M x L = ?
molsl KHP = mols NaOH (from the coefficients in the balanced equation).
Then mols KHP = grams KHP/molar mass KHP. You know molar mass and mols solve for grams KHP.
So, Mols NaOH = 0.2264 M NaOH x 0.04936 L NaOH = 0.011175
Mols KHP = grams KHP / molar mass KHP or
grams KHP = Mols KHP x molar mass KHP so
0.011175 x 204.22 = 2.2822 grams of KHP
Is that correct DBob222?
Yes, that is correct(almost); however, you have used too many significant figures. The 49.36 number limits the number of s.f. to four; therefore, you may have only four in the final answer. That means you should round your final answer to 2.282 g KHP.
To solve this problem, we can use the concept of stoichiometry and the formula of the balanced chemical equation involved in the titration. Here's a step-by-step explanation of how to approach this problem:
1. Write the balanced chemical equation: In this case, it's a titration between NaOH (sodium hydroxide) and KHP (potassium hydrogen phthalate). The balanced equation is as follows:
NaOH + KHP -> NaKP + H2O
2. Determine the stoichiometry: From the balanced equation, we can see that the reaction occurs in a 1:1 ratio between NaOH and KHP.
3. Calculate the moles of NaOH used: To do this, we need to use the formula: Molarity (M) = Moles (mol) / Volume (L). Rearranging this formula, we get: Moles (mol) = Molarity (M) x Volume (L). Given that the volume of NaOH used is 49.36 mL (or 0.04936 L) and the molarity is 0.2264 M, we can calculate the moles of NaOH used:
Moles of NaOH = 0.2264 M x 0.04936 L = 0.011172 moles
4. Use the stoichiometry to determine moles of KHP: Since the reaction occurs in a 1:1 ratio between NaOH and KHP, the moles of NaOH used are equal to the moles of KHP present in the container.
5. Calculate the mass of KHP: To calculate the mass of KHP, we need to use its molar mass. Given that the molar mass of KHP is 204.22 g/mol, we can calculate the mass of KHP:
Mass of KHP = Moles of KHP x Molar mass of KHP
= 0.011172 moles x 204.22 g/mol
= 2.2793 grams
Therefore, there were approximately 2.2793 grams of KHP present in the container.